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5x^2+130x+125=0
a = 5; b = 130; c = +125;
Δ = b2-4ac
Δ = 1302-4·5·125
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(130)-120}{2*5}=\frac{-250}{10} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(130)+120}{2*5}=\frac{-10}{10} =-1 $
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